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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Peter Falcone
Peter Falcone
Courses Plus Student 1,108 Points

a little confusion with even.py

this is my best shot, haven't submitted it yet, because for one thing, I really don't know what to do with the "return not num % 2" bit, so as you can see, I just wrote what made sense to me

even.py 
import random

start = 5
while start:
    num = random.randint(1, 99)
    if start = False:
        break
def even_odd(num):
    if num % 2 == 0:
        print("{} is even").format(num)
    elif num % 2 != 0:
        print("{} is odd").format(num)
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

start -= 1

1 Answer

Christopher Shaw
.a{fill-rule:evenodd;}techdegree seal-36
Christopher Shaw
Python Web Development Techdegree Graduate 58,248 Points

Unfortunately, not on track. You should have left even_odd as it was and called the function as you needed it to test a value. So after the original function, start the while loop. 

if not even_odd(num): 
# matches false

#or
if even_odd(num): 
#matches true
Peter Falcone
Peter Falcone
Courses Plus Student 1,108 Points

just gonna keep working at it then, thanks