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JavaScript JavaScript Basics (Retired) Making Decisions with Conditional Statements The Conditional Challenge

Posted by Jake Guss
.a{fill-rule:evenodd;}techdegree
Jake Guss
Front End Web Development Techdegree Student 5,855 Points

All my quiz responses come back as correct answers.

//All answers to firstAnswer are considered correct. What's am I doing wrong?

var rightAnswers = 0;
var correct = "You're correct!";
var wrong = "You're wrong.";

alert('Welcome to the quiz. This quiz consists of 5 questions. good luck!');
var firstAnswer = prompt('How many states are there in the U.S.A.?');
if (firstAnswer === 'fifty' || parseInt('50')) { alert(correct);
rightAnswers +=1;
    }
else {alert(wrong);
     }

3 Answers

Robert Lyon
Robert Lyon
7,551 Points
Robert Lyon
Robert Lyon
7,551 Points

Yeah i just noticed the parseInt part. Try this one. (firstAnswer === 'fifty' || parseInt(firstAnswer) === 50)

Robert Lyon
Robert Lyon
7,551 Points
Robert Lyon
Robert Lyon
7,551 Points

Within the if statement try changing the condition to, (firstAnswer === 'fifty' || firstAnswer === parseInt('50'))

Jake Guss
seal-mask
.a{fill-rule:evenodd;}techdegree
Jake Guss
Front End Web Development Techdegree Student 5,855 Points
Jake Guss
.a{fill-rule:evenodd;}techdegree
Jake Guss
Front End Web Development Techdegree Student 5,855 Points

I am now listed as being wrong when inputting the integer 50, , whether I put string quotes around parseInt('50') or not.

Irfan Hussain
Irfan Hussain
Courses Plus Student 6,593 Points

Yes its wrong if you add string sing with numeric value. I will explain: You are trying to convert user input to integer value then try to pass it with string value. How its possible. More detail: 1) You enter 50 on prompt. 2) Value was string your convert to integer. 3) Then you try to pass with string again.

I hope this will help you.