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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Passing an Argument to a Function

i just dont understand the task. its just not working as described in the video

please just give me a hint to the solution beacuse i dont see any solution hints in de the video

script.js
function returnValue(anything){
  var echo;


  return anything;
}

returnValue("hello");
index.html
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

2 Answers

Hi,

You were pretty close, the wording is a bit tricky, it says to create a variable 'echo' but it is not to be inside the function, it is to equal the return value from the function, so place it outside and make equal to the function call:

function returnValue(anything){
  return anything;
}

var echo = returnValue("hello");

thank you very much :) makes sense! but i couldn t find any explanation to that in the video ....anyway :) thanks alot

No probs :) Yeh, sometimes the wording is hard to understand.