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Java Java Basics Perfecting the Prototype Looping until the value passes

Last exercise, third question.

Hi,

I do not know where to put console.readLine... prompt. Can you help me please? :)

Thanks!

Example.java
// I have initialized a java.io.Console for you. It is in a variable named console.
String response;
do {
  response  = console.readLine("Do you understand do while loops?  ");
  if(response.equalsIgnoreCase("No"));
} while(response.equalsIgnoreCase("No"));
if(response.equalsIgnoreCase("Yes")); {
  console.printf("Because you said %, you passed the test", response);
}

2 Answers

You forgot the s in %s. Also, there is not need for the if statement inside the loop. The loop condition is taking care of that. Also if you reach outside the loop it means the answer was yes so there is no need for an if statement there either:

// I have initialized a java.io.Console for you. It is in a variable named console.
String response;
do {
  response  = console.readLine("Do you understand do while loops?  ");
} while(response.equalsIgnoreCase("No"));
console.printf("Because you said %s, you passed the test!", response);

How is %s being used? Does it display the response from the console so long as it equals "No"?

You need the %s so that printf inserts the content of response there. Also, we use %s since response is a String. For an int variable you can use %d.

Thanks, now it is working! :)