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Python Regular Expressions in Python Introduction to Regular Expressions Players Dictionary and Class

Posted by Yuqing Lu
Yuqing Lu
7,032 Points

Need Help!!!

Hi, anyone can suggest how do I correct this code. In pyCharm, this code can only output one result instead of a list, for example, if some_player is a instance of Player(), print(some_player.last_name) can only get "Steward Pinchback" but not the whole list of all last_names. and of course, it won't pass the challenge. however I am more concerned with how to make the code to work as I expect other than passing a test. thank you!!!

players.py 
import re

string = '''Love, Kenneth: 20
Chalkley, Andrew: 25
McFarland, Dave: 10
Kesten, Joy: 22
Stewart Pinchback, Pinckney Benton: 18'''

players = re.search('''
    ^(?P<last_name>[\w\s]+)
    ,\s
    (?P<first_name>[\w\s]+)
    :\s
    (?P<score>\d{2})$
''', string, re.X|re.M)


class Player:
    line = re.compile('''
                           ^(?P<last_name>[\w\s]+)
                             ,\s
                            (?P<first_name>[\w\s]+)
                            :\s
                             (?P<score>\d{2})$
                        ''', re.X | re.M)

    def __init__(self, string):
        for match in self.line.finditer(string):
            self.last_name = match.group('last_name')
            self.first_name = match.group('first_name')
            self.score = match.group('score')

1 Answer

Christopher Shaw
.a{fill-rule:evenodd;}techdegree seal-36
Christopher Shaw
Python Web Development Techdegree Graduate 58,248 Points

Without looking at the challenge, but just your question, you say you only get "Steward Pinchback" back, which is the last name in the list. This is because for each iteration of the for loop, the self.last_name, first and score is set, overriding the previous name that was set. If you want it to return a list, you need to create a list, at the moment you have only variables.

Yuqing Lu
Yuqing Lu
7,032 Points

Hi, Christopher, Thank you again, you really pointed it out!