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Java Java Basics Perfecting the Prototype String Equality

Problem at second if statement!

how can i get hello word with ignore case first example equal to third example

Equality.java
// I have imported a java.io.Console for you, it is named console. 
String firstExample = "hello";
String secondExample = "hello";
String thirdExample = "HELLO";
if(firstExample==secondExample)
{
  console.printf("first is equal to second");
}
if(thirdExample.equalsIgnorecase("hello")==firstExample)
{
  console.printf("first and third are the same ignoring case");
}

1 Answer

Hello Mayur,

Do you get any error on this? As I can see that equalsIgnoreCase() is the function and not equalsIgnorecase(). [Remember the camel case notation].

Also, thirdExample.equalsIgnorecase("hello") will return you a boolean value and then you are comparing it with firstExample which is a string. This will never be equal. I would say do something like this:

if(thirdExample.equalsIgnoreCase("hello")){
//your stuff
}

Thank you Nikhil! problem solved :)

Please upvote if you think this helped you. Thanks :)