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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Posted by roshaan zafar
roshaan zafar
3,868 Points

what could be the problem

rectify me please

Name.java 
String firstName="roshaan";
console.printf("roshaan");

4 Answers

Daniel Szepanski
PLUS
Daniel Szepanski
Courses Plus Student 5,098 Points
Daniel Szepanski
Daniel Szepanski
Courses Plus Student 5,098 Points

Hi, try to declare your console like -> 

Console cons = System.console();
String firstName = "roshaan";
cons.printf("Hallo %s", firstName);  // <--don't forget to use your variable

or as Aymen Hachicha said use System.out.printf("Hallo %s", firstName);

Hope i could help you.

Aymen Hachicha
Aymen Hachicha
12,653 Points
Aymen Hachicha
Aymen Hachicha
12,653 Points

It's System.out.printf(); not console.printf :)

Matthias Nörr
Matthias Nörr
8,614 Points
Matthias Nörr
Matthias Nörr
8,614 Points 
String firstName = "roshaan";
System.out.print(firstName);

The problem is still there. In the first line you create a new variable called firstName and store "roshaan" inside. If you want to print out the String-Variable you have to insert the name of the variable into the print-command.

Aymen Hachicha
Aymen Hachicha
12,653 Points
Aymen Hachicha
Aymen Hachicha
12,653 Points

printf or println not print ..

Matthias Nörr
Matthias Nörr
8,614 Points

System.out.print does also compile. It just does not look pretty.